Integrand size = 14, antiderivative size = 364 \[ \int \left (b \tan ^3(e+f x)\right )^{5/2} \, dx=-\frac {2 b^2 \cot (e+f x) \sqrt {b \tan ^3(e+f x)}}{f}-\frac {b^2 \arctan \left (1-\sqrt {2} \sqrt {\tan (e+f x)}\right ) \sqrt {b \tan ^3(e+f x)}}{\sqrt {2} f \tan ^{\frac {3}{2}}(e+f x)}+\frac {b^2 \arctan \left (1+\sqrt {2} \sqrt {\tan (e+f x)}\right ) \sqrt {b \tan ^3(e+f x)}}{\sqrt {2} f \tan ^{\frac {3}{2}}(e+f x)}-\frac {b^2 \log \left (1-\sqrt {2} \sqrt {\tan (e+f x)}+\tan (e+f x)\right ) \sqrt {b \tan ^3(e+f x)}}{2 \sqrt {2} f \tan ^{\frac {3}{2}}(e+f x)}+\frac {b^2 \log \left (1+\sqrt {2} \sqrt {\tan (e+f x)}+\tan (e+f x)\right ) \sqrt {b \tan ^3(e+f x)}}{2 \sqrt {2} f \tan ^{\frac {3}{2}}(e+f x)}+\frac {2 b^2 \tan (e+f x) \sqrt {b \tan ^3(e+f x)}}{5 f}-\frac {2 b^2 \tan ^3(e+f x) \sqrt {b \tan ^3(e+f x)}}{9 f}+\frac {2 b^2 \tan ^5(e+f x) \sqrt {b \tan ^3(e+f x)}}{13 f} \]
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Time = 0.18 (sec) , antiderivative size = 364, normalized size of antiderivative = 1.00, number of steps used = 16, number of rules used = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.714, Rules used = {3739, 3554, 3557, 335, 217, 1179, 642, 1176, 631, 210} \[ \int \left (b \tan ^3(e+f x)\right )^{5/2} \, dx=-\frac {b^2 \arctan \left (1-\sqrt {2} \sqrt {\tan (e+f x)}\right ) \sqrt {b \tan ^3(e+f x)}}{\sqrt {2} f \tan ^{\frac {3}{2}}(e+f x)}+\frac {b^2 \arctan \left (\sqrt {2} \sqrt {\tan (e+f x)}+1\right ) \sqrt {b \tan ^3(e+f x)}}{\sqrt {2} f \tan ^{\frac {3}{2}}(e+f x)}-\frac {2 b^2 \tan ^3(e+f x) \sqrt {b \tan ^3(e+f x)}}{9 f}+\frac {2 b^2 \tan (e+f x) \sqrt {b \tan ^3(e+f x)}}{5 f}+\frac {2 b^2 \tan ^5(e+f x) \sqrt {b \tan ^3(e+f x)}}{13 f}-\frac {b^2 \sqrt {b \tan ^3(e+f x)} \log \left (\tan (e+f x)-\sqrt {2} \sqrt {\tan (e+f x)}+1\right )}{2 \sqrt {2} f \tan ^{\frac {3}{2}}(e+f x)}+\frac {b^2 \sqrt {b \tan ^3(e+f x)} \log \left (\tan (e+f x)+\sqrt {2} \sqrt {\tan (e+f x)}+1\right )}{2 \sqrt {2} f \tan ^{\frac {3}{2}}(e+f x)}-\frac {2 b^2 \cot (e+f x) \sqrt {b \tan ^3(e+f x)}}{f} \]
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Rule 210
Rule 217
Rule 335
Rule 631
Rule 642
Rule 1176
Rule 1179
Rule 3554
Rule 3557
Rule 3739
Rubi steps \begin{align*} \text {integral}& = \frac {\left (b^2 \sqrt {b \tan ^3(e+f x)}\right ) \int \tan ^{\frac {15}{2}}(e+f x) \, dx}{\tan ^{\frac {3}{2}}(e+f x)} \\ & = \frac {2 b^2 \tan ^5(e+f x) \sqrt {b \tan ^3(e+f x)}}{13 f}-\frac {\left (b^2 \sqrt {b \tan ^3(e+f x)}\right ) \int \tan ^{\frac {11}{2}}(e+f x) \, dx}{\tan ^{\frac {3}{2}}(e+f x)} \\ & = -\frac {2 b^2 \tan ^3(e+f x) \sqrt {b \tan ^3(e+f x)}}{9 f}+\frac {2 b^2 \tan ^5(e+f x) \sqrt {b \tan ^3(e+f x)}}{13 f}+\frac {\left (b^2 \sqrt {b \tan ^3(e+f x)}\right ) \int \tan ^{\frac {7}{2}}(e+f x) \, dx}{\tan ^{\frac {3}{2}}(e+f x)} \\ & = \frac {2 b^2 \tan (e+f x) \sqrt {b \tan ^3(e+f x)}}{5 f}-\frac {2 b^2 \tan ^3(e+f x) \sqrt {b \tan ^3(e+f x)}}{9 f}+\frac {2 b^2 \tan ^5(e+f x) \sqrt {b \tan ^3(e+f x)}}{13 f}-\frac {\left (b^2 \sqrt {b \tan ^3(e+f x)}\right ) \int \tan ^{\frac {3}{2}}(e+f x) \, dx}{\tan ^{\frac {3}{2}}(e+f x)} \\ & = -\frac {2 b^2 \cot (e+f x) \sqrt {b \tan ^3(e+f x)}}{f}+\frac {2 b^2 \tan (e+f x) \sqrt {b \tan ^3(e+f x)}}{5 f}-\frac {2 b^2 \tan ^3(e+f x) \sqrt {b \tan ^3(e+f x)}}{9 f}+\frac {2 b^2 \tan ^5(e+f x) \sqrt {b \tan ^3(e+f x)}}{13 f}+\frac {\left (b^2 \sqrt {b \tan ^3(e+f x)}\right ) \int \frac {1}{\sqrt {\tan (e+f x)}} \, dx}{\tan ^{\frac {3}{2}}(e+f x)} \\ & = -\frac {2 b^2 \cot (e+f x) \sqrt {b \tan ^3(e+f x)}}{f}+\frac {2 b^2 \tan (e+f x) \sqrt {b \tan ^3(e+f x)}}{5 f}-\frac {2 b^2 \tan ^3(e+f x) \sqrt {b \tan ^3(e+f x)}}{9 f}+\frac {2 b^2 \tan ^5(e+f x) \sqrt {b \tan ^3(e+f x)}}{13 f}+\frac {\left (b^2 \sqrt {b \tan ^3(e+f x)}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {x} \left (1+x^2\right )} \, dx,x,\tan (e+f x)\right )}{f \tan ^{\frac {3}{2}}(e+f x)} \\ & = -\frac {2 b^2 \cot (e+f x) \sqrt {b \tan ^3(e+f x)}}{f}+\frac {2 b^2 \tan (e+f x) \sqrt {b \tan ^3(e+f x)}}{5 f}-\frac {2 b^2 \tan ^3(e+f x) \sqrt {b \tan ^3(e+f x)}}{9 f}+\frac {2 b^2 \tan ^5(e+f x) \sqrt {b \tan ^3(e+f x)}}{13 f}+\frac {\left (2 b^2 \sqrt {b \tan ^3(e+f x)}\right ) \text {Subst}\left (\int \frac {1}{1+x^4} \, dx,x,\sqrt {\tan (e+f x)}\right )}{f \tan ^{\frac {3}{2}}(e+f x)} \\ & = -\frac {2 b^2 \cot (e+f x) \sqrt {b \tan ^3(e+f x)}}{f}+\frac {2 b^2 \tan (e+f x) \sqrt {b \tan ^3(e+f x)}}{5 f}-\frac {2 b^2 \tan ^3(e+f x) \sqrt {b \tan ^3(e+f x)}}{9 f}+\frac {2 b^2 \tan ^5(e+f x) \sqrt {b \tan ^3(e+f x)}}{13 f}+\frac {\left (b^2 \sqrt {b \tan ^3(e+f x)}\right ) \text {Subst}\left (\int \frac {1-x^2}{1+x^4} \, dx,x,\sqrt {\tan (e+f x)}\right )}{f \tan ^{\frac {3}{2}}(e+f x)}+\frac {\left (b^2 \sqrt {b \tan ^3(e+f x)}\right ) \text {Subst}\left (\int \frac {1+x^2}{1+x^4} \, dx,x,\sqrt {\tan (e+f x)}\right )}{f \tan ^{\frac {3}{2}}(e+f x)} \\ & = -\frac {2 b^2 \cot (e+f x) \sqrt {b \tan ^3(e+f x)}}{f}+\frac {2 b^2 \tan (e+f x) \sqrt {b \tan ^3(e+f x)}}{5 f}-\frac {2 b^2 \tan ^3(e+f x) \sqrt {b \tan ^3(e+f x)}}{9 f}+\frac {2 b^2 \tan ^5(e+f x) \sqrt {b \tan ^3(e+f x)}}{13 f}+\frac {\left (b^2 \sqrt {b \tan ^3(e+f x)}\right ) \text {Subst}\left (\int \frac {1}{1-\sqrt {2} x+x^2} \, dx,x,\sqrt {\tan (e+f x)}\right )}{2 f \tan ^{\frac {3}{2}}(e+f x)}+\frac {\left (b^2 \sqrt {b \tan ^3(e+f x)}\right ) \text {Subst}\left (\int \frac {1}{1+\sqrt {2} x+x^2} \, dx,x,\sqrt {\tan (e+f x)}\right )}{2 f \tan ^{\frac {3}{2}}(e+f x)}-\frac {\left (b^2 \sqrt {b \tan ^3(e+f x)}\right ) \text {Subst}\left (\int \frac {\sqrt {2}+2 x}{-1-\sqrt {2} x-x^2} \, dx,x,\sqrt {\tan (e+f x)}\right )}{2 \sqrt {2} f \tan ^{\frac {3}{2}}(e+f x)}-\frac {\left (b^2 \sqrt {b \tan ^3(e+f x)}\right ) \text {Subst}\left (\int \frac {\sqrt {2}-2 x}{-1+\sqrt {2} x-x^2} \, dx,x,\sqrt {\tan (e+f x)}\right )}{2 \sqrt {2} f \tan ^{\frac {3}{2}}(e+f x)} \\ & = -\frac {2 b^2 \cot (e+f x) \sqrt {b \tan ^3(e+f x)}}{f}-\frac {b^2 \log \left (1-\sqrt {2} \sqrt {\tan (e+f x)}+\tan (e+f x)\right ) \sqrt {b \tan ^3(e+f x)}}{2 \sqrt {2} f \tan ^{\frac {3}{2}}(e+f x)}+\frac {b^2 \log \left (1+\sqrt {2} \sqrt {\tan (e+f x)}+\tan (e+f x)\right ) \sqrt {b \tan ^3(e+f x)}}{2 \sqrt {2} f \tan ^{\frac {3}{2}}(e+f x)}+\frac {2 b^2 \tan (e+f x) \sqrt {b \tan ^3(e+f x)}}{5 f}-\frac {2 b^2 \tan ^3(e+f x) \sqrt {b \tan ^3(e+f x)}}{9 f}+\frac {2 b^2 \tan ^5(e+f x) \sqrt {b \tan ^3(e+f x)}}{13 f}+\frac {\left (b^2 \sqrt {b \tan ^3(e+f x)}\right ) \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\sqrt {2} \sqrt {\tan (e+f x)}\right )}{\sqrt {2} f \tan ^{\frac {3}{2}}(e+f x)}-\frac {\left (b^2 \sqrt {b \tan ^3(e+f x)}\right ) \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\sqrt {2} \sqrt {\tan (e+f x)}\right )}{\sqrt {2} f \tan ^{\frac {3}{2}}(e+f x)} \\ & = -\frac {2 b^2 \cot (e+f x) \sqrt {b \tan ^3(e+f x)}}{f}-\frac {b^2 \arctan \left (1-\sqrt {2} \sqrt {\tan (e+f x)}\right ) \sqrt {b \tan ^3(e+f x)}}{\sqrt {2} f \tan ^{\frac {3}{2}}(e+f x)}+\frac {b^2 \arctan \left (1+\sqrt {2} \sqrt {\tan (e+f x)}\right ) \sqrt {b \tan ^3(e+f x)}}{\sqrt {2} f \tan ^{\frac {3}{2}}(e+f x)}-\frac {b^2 \log \left (1-\sqrt {2} \sqrt {\tan (e+f x)}+\tan (e+f x)\right ) \sqrt {b \tan ^3(e+f x)}}{2 \sqrt {2} f \tan ^{\frac {3}{2}}(e+f x)}+\frac {b^2 \log \left (1+\sqrt {2} \sqrt {\tan (e+f x)}+\tan (e+f x)\right ) \sqrt {b \tan ^3(e+f x)}}{2 \sqrt {2} f \tan ^{\frac {3}{2}}(e+f x)}+\frac {2 b^2 \tan (e+f x) \sqrt {b \tan ^3(e+f x)}}{5 f}-\frac {2 b^2 \tan ^3(e+f x) \sqrt {b \tan ^3(e+f x)}}{9 f}+\frac {2 b^2 \tan ^5(e+f x) \sqrt {b \tan ^3(e+f x)}}{13 f} \\ \end{align*}
Time = 1.05 (sec) , antiderivative size = 204, normalized size of antiderivative = 0.56 \[ \int \left (b \tan ^3(e+f x)\right )^{5/2} \, dx=\frac {\left (b \tan ^3(e+f x)\right )^{5/2} \left (-\frac {\arctan \left (1-\sqrt {2} \sqrt {\tan (e+f x)}\right )}{\sqrt {2}}+\frac {\arctan \left (1+\sqrt {2} \sqrt {\tan (e+f x)}\right )}{\sqrt {2}}-\frac {\log \left (1-\sqrt {2} \sqrt {\tan (e+f x)}+\tan (e+f x)\right )}{2 \sqrt {2}}+\frac {\log \left (1+\sqrt {2} \sqrt {\tan (e+f x)}+\tan (e+f x)\right )}{2 \sqrt {2}}-2 \sqrt {\tan (e+f x)}+\frac {2}{5} \tan ^{\frac {5}{2}}(e+f x)-\frac {2}{9} \tan ^{\frac {9}{2}}(e+f x)+\frac {2}{13} \tan ^{\frac {13}{2}}(e+f x)\right )}{f \tan ^{\frac {15}{2}}(e+f x)} \]
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Time = 0.11 (sec) , antiderivative size = 266, normalized size of antiderivative = 0.73
method | result | size |
derivativedivides | \(\frac {\left (b \tan \left (f x +e \right )^{3}\right )^{\frac {5}{2}} \left (360 \left (b \tan \left (f x +e \right )\right )^{\frac {13}{2}}-520 b^{2} \left (b \tan \left (f x +e \right )\right )^{\frac {9}{2}}+585 b^{6} \left (b^{2}\right )^{\frac {1}{4}} \sqrt {2}\, \ln \left (-\frac {b \tan \left (f x +e \right )+\left (b^{2}\right )^{\frac {1}{4}} \sqrt {b \tan \left (f x +e \right )}\, \sqrt {2}+\sqrt {b^{2}}}{\left (b^{2}\right )^{\frac {1}{4}} \sqrt {b \tan \left (f x +e \right )}\, \sqrt {2}-b \tan \left (f x +e \right )-\sqrt {b^{2}}}\right )+1170 b^{6} \left (b^{2}\right )^{\frac {1}{4}} \sqrt {2}\, \arctan \left (\frac {\sqrt {2}\, \sqrt {b \tan \left (f x +e \right )}+\left (b^{2}\right )^{\frac {1}{4}}}{\left (b^{2}\right )^{\frac {1}{4}}}\right )+1170 b^{6} \left (b^{2}\right )^{\frac {1}{4}} \sqrt {2}\, \arctan \left (\frac {\sqrt {2}\, \sqrt {b \tan \left (f x +e \right )}-\left (b^{2}\right )^{\frac {1}{4}}}{\left (b^{2}\right )^{\frac {1}{4}}}\right )+936 b^{4} \left (b \tan \left (f x +e \right )\right )^{\frac {5}{2}}-4680 b^{6} \sqrt {b \tan \left (f x +e \right )}\right )}{2340 f \tan \left (f x +e \right )^{5} \left (b \tan \left (f x +e \right )\right )^{\frac {5}{2}} b^{4}}\) | \(266\) |
default | \(\frac {\left (b \tan \left (f x +e \right )^{3}\right )^{\frac {5}{2}} \left (360 \left (b \tan \left (f x +e \right )\right )^{\frac {13}{2}}-520 b^{2} \left (b \tan \left (f x +e \right )\right )^{\frac {9}{2}}+585 b^{6} \left (b^{2}\right )^{\frac {1}{4}} \sqrt {2}\, \ln \left (-\frac {b \tan \left (f x +e \right )+\left (b^{2}\right )^{\frac {1}{4}} \sqrt {b \tan \left (f x +e \right )}\, \sqrt {2}+\sqrt {b^{2}}}{\left (b^{2}\right )^{\frac {1}{4}} \sqrt {b \tan \left (f x +e \right )}\, \sqrt {2}-b \tan \left (f x +e \right )-\sqrt {b^{2}}}\right )+1170 b^{6} \left (b^{2}\right )^{\frac {1}{4}} \sqrt {2}\, \arctan \left (\frac {\sqrt {2}\, \sqrt {b \tan \left (f x +e \right )}+\left (b^{2}\right )^{\frac {1}{4}}}{\left (b^{2}\right )^{\frac {1}{4}}}\right )+1170 b^{6} \left (b^{2}\right )^{\frac {1}{4}} \sqrt {2}\, \arctan \left (\frac {\sqrt {2}\, \sqrt {b \tan \left (f x +e \right )}-\left (b^{2}\right )^{\frac {1}{4}}}{\left (b^{2}\right )^{\frac {1}{4}}}\right )+936 b^{4} \left (b \tan \left (f x +e \right )\right )^{\frac {5}{2}}-4680 b^{6} \sqrt {b \tan \left (f x +e \right )}\right )}{2340 f \tan \left (f x +e \right )^{5} \left (b \tan \left (f x +e \right )\right )^{\frac {5}{2}} b^{4}}\) | \(266\) |
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Result contains complex when optimal does not.
Time = 0.27 (sec) , antiderivative size = 332, normalized size of antiderivative = 0.91 \[ \int \left (b \tan ^3(e+f x)\right )^{5/2} \, dx=\frac {585 \, \left (-\frac {b^{10}}{f^{4}}\right )^{\frac {1}{4}} f \log \left (\frac {\sqrt {b \tan \left (f x + e\right )^{3}} b^{2} + \left (-\frac {b^{10}}{f^{4}}\right )^{\frac {1}{4}} f \tan \left (f x + e\right )}{\tan \left (f x + e\right )}\right ) \tan \left (f x + e\right ) + 585 i \, \left (-\frac {b^{10}}{f^{4}}\right )^{\frac {1}{4}} f \log \left (\frac {\sqrt {b \tan \left (f x + e\right )^{3}} b^{2} + i \, \left (-\frac {b^{10}}{f^{4}}\right )^{\frac {1}{4}} f \tan \left (f x + e\right )}{\tan \left (f x + e\right )}\right ) \tan \left (f x + e\right ) - 585 i \, \left (-\frac {b^{10}}{f^{4}}\right )^{\frac {1}{4}} f \log \left (\frac {\sqrt {b \tan \left (f x + e\right )^{3}} b^{2} - i \, \left (-\frac {b^{10}}{f^{4}}\right )^{\frac {1}{4}} f \tan \left (f x + e\right )}{\tan \left (f x + e\right )}\right ) \tan \left (f x + e\right ) - 585 \, \left (-\frac {b^{10}}{f^{4}}\right )^{\frac {1}{4}} f \log \left (\frac {\sqrt {b \tan \left (f x + e\right )^{3}} b^{2} - \left (-\frac {b^{10}}{f^{4}}\right )^{\frac {1}{4}} f \tan \left (f x + e\right )}{\tan \left (f x + e\right )}\right ) \tan \left (f x + e\right ) + 4 \, {\left (45 \, b^{2} \tan \left (f x + e\right )^{6} - 65 \, b^{2} \tan \left (f x + e\right )^{4} + 117 \, b^{2} \tan \left (f x + e\right )^{2} - 585 \, b^{2}\right )} \sqrt {b \tan \left (f x + e\right )^{3}}}{1170 \, f \tan \left (f x + e\right )} \]
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\[ \int \left (b \tan ^3(e+f x)\right )^{5/2} \, dx=\int \left (b \tan ^{3}{\left (e + f x \right )}\right )^{\frac {5}{2}}\, dx \]
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Time = 0.41 (sec) , antiderivative size = 178, normalized size of antiderivative = 0.49 \[ \int \left (b \tan ^3(e+f x)\right )^{5/2} \, dx=\frac {360 \, b^{\frac {5}{2}} \tan \left (f x + e\right )^{\frac {13}{2}} - 520 \, b^{\frac {5}{2}} \tan \left (f x + e\right )^{\frac {9}{2}} + 936 \, b^{\frac {5}{2}} \tan \left (f x + e\right )^{\frac {5}{2}} + 585 \, {\left (2 \, \sqrt {2} \sqrt {b} \arctan \left (\frac {1}{2} \, \sqrt {2} {\left (\sqrt {2} + 2 \, \sqrt {\tan \left (f x + e\right )}\right )}\right ) + 2 \, \sqrt {2} \sqrt {b} \arctan \left (-\frac {1}{2} \, \sqrt {2} {\left (\sqrt {2} - 2 \, \sqrt {\tan \left (f x + e\right )}\right )}\right ) + \sqrt {2} \sqrt {b} \log \left (\sqrt {2} \sqrt {\tan \left (f x + e\right )} + \tan \left (f x + e\right ) + 1\right ) - \sqrt {2} \sqrt {b} \log \left (-\sqrt {2} \sqrt {\tan \left (f x + e\right )} + \tan \left (f x + e\right ) + 1\right )\right )} b^{2} - 4680 \, b^{\frac {5}{2}} \sqrt {\tan \left (f x + e\right )}}{2340 \, f} \]
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Time = 0.46 (sec) , antiderivative size = 291, normalized size of antiderivative = 0.80 \[ \int \left (b \tan ^3(e+f x)\right )^{5/2} \, dx=\frac {1}{2340} \, {\left (\frac {1170 \, \sqrt {2} b \sqrt {{\left | b \right |}} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} \sqrt {{\left | b \right |}} + 2 \, \sqrt {b \tan \left (f x + e\right )}\right )}}{2 \, \sqrt {{\left | b \right |}}}\right )}{f} + \frac {1170 \, \sqrt {2} b \sqrt {{\left | b \right |}} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} \sqrt {{\left | b \right |}} - 2 \, \sqrt {b \tan \left (f x + e\right )}\right )}}{2 \, \sqrt {{\left | b \right |}}}\right )}{f} + \frac {585 \, \sqrt {2} b \sqrt {{\left | b \right |}} \log \left (b \tan \left (f x + e\right ) + \sqrt {2} \sqrt {b \tan \left (f x + e\right )} \sqrt {{\left | b \right |}} + {\left | b \right |}\right )}{f} - \frac {585 \, \sqrt {2} b \sqrt {{\left | b \right |}} \log \left (b \tan \left (f x + e\right ) - \sqrt {2} \sqrt {b \tan \left (f x + e\right )} \sqrt {{\left | b \right |}} + {\left | b \right |}\right )}{f} + \frac {8 \, {\left (45 \, \sqrt {b \tan \left (f x + e\right )} b^{66} f^{12} \tan \left (f x + e\right )^{6} - 65 \, \sqrt {b \tan \left (f x + e\right )} b^{66} f^{12} \tan \left (f x + e\right )^{4} + 117 \, \sqrt {b \tan \left (f x + e\right )} b^{66} f^{12} \tan \left (f x + e\right )^{2} - 585 \, \sqrt {b \tan \left (f x + e\right )} b^{66} f^{12}\right )}}{b^{65} f^{13}}\right )} b \mathrm {sgn}\left (\tan \left (f x + e\right )\right ) \]
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Timed out. \[ \int \left (b \tan ^3(e+f x)\right )^{5/2} \, dx=\int {\left (b\,{\mathrm {tan}\left (e+f\,x\right )}^3\right )}^{5/2} \,d x \]
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